Question about arrays.

  • What is the proper way to work with arrays that have been generated with a for loop and push?
    Excuse if my terminology is not correct. I'm fairly new to openjscad and js as a whole.

    In essence I have an array of positions and want to punch holes in a plate at those positions.

    I am trying with the following:

    function pcb () {
        pcb_width = 25;
        pcb_height = 3;
        pcb_thickness = 50;
        pcb_dimmensions = [(pcb_width), (pcb_thickness), (pcb_height)];
        return cube(pcb_dimmensions);
    function holes1 () {
        var array = [];
                        cylinder({h: 20})));
                        cylinder({h: 20})));
        return array;
    function holes2 () {
        var holes = [];
        var positions = [
            [4, 12, -1],
            [8, 12, -1],
            [8, 18, -1],
            [12, 18, -1],
        for (i=0; i <= positions.length; i++) {
                    cylinder({h: 10})))
        return holes
    function main () {
        //return holes2 ();
        //why does return [pcb()] work but not return [holes1(), or holes2()] ?
        //return [pcb(),holes1()] //does not work
        //return difference (pcb(),holes1());      // does not works
        return union (pcb(),holes1());      //works
        //return union (pcb(),holes2());    //does not work


    1. Why can I not return an array consisting of the pcb and the holes-array (cylinders)? Is nesting a problem here?
    2. Union of pcb() and holes1() works, but not if holes2() is used. The function which includes a for loop.
    3. Difference of pcb() and holes() works for neither.

    As a side note, I am assuming the community hangs here and not on IRC or such?
    Looking for a place to quickly solve some doubts to help me get on my feet.

  • @jarshvor another way to look at this is the return types...

    pcb() returns an object (1)
    holes1() returns an array of objects (2)
    holes2() returns an array of objects (4)

    V1 requires main() to return an ARRAY of objects or a single object.
    (FYI, V2 automatically flattens everything into an array.)

    @gilboonet is correct in the example provided. By using '...holes1()' syntax, an array is constructed from [ pcb(), holes1[0], holes1[1] ]

    Hang in there. You'll get it soon. 🙂

  • I recently had same trouble with arrays. If you want to return your values without being forced to union them, you can use ... on those who are iterable (mainly arrays).

    pcb() returns a value, so it is not iterable, you return it directly
    holes1() returns an array so you can return ...holes1()

    put together that makes

    return [pcb(), ...holes1()]

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